51. 200 g of 25% sulphuric acid solution was added to 300 g of 40% sulphuric acid solution. Find the concentration of the acid in the mixture.
A. 14%
B. 24%
C. 44%
D. 34%
Answer & Explanation
Option D
Amount of acid in the 1st solution = 0.25 × 200 = 50 g.
Amount of acid in the 2nd solution = 0.4 × 300 = 120 g.
Total amount of acid = 50 + 120 = 170 g. ∴ Required concentration = 170 / (200 + 300) × 100 = 34%
52. In one alloy there is 60% gold in its total mass, while in another alloy it is 35%. 12 kg of the first alloy was melted together with 8 kg of the second one to form a third alloy. Find the percentage of gold in the new alloy.
A. 50%
B. 49%
C. 45%
D. 48%
Answer & Explanation
Option A
Amount of gold in 1st alloy = 0.6 × 12 = 7.2 kg. Amount of gold in
2nd alloy = 0.35 × 8 =2.8 kg.
∴
required % age of gold = (7.2 + 2.8) / (12 + 8) × 100 = (10 / 20) × 100 = 50 %
53. Answer & Explanation
Option A
Amount of gold in 1st alloy = 0.6 × 12 = 7.2 kg. Amount of gold in
2nd alloy = 0.35 × 8 =2.8 kg.
∴
required % age of gold = (7.2 + 2.8) / (12 + 8) ×
100 = (10 / 20) × 100 = 50 %.
54. 300 coins consists of 1 rupee, 50 paise and 25 paise coins, their values being in the ratio of 10 : 4 : C. Find the number of coins of each type.
A. 100, 80, 120
B. 80, 90, 100
C. 100, 100, 80
D. 60, 80, 100
Answer & Explanation
Option A
Value of rupee coins = 10 i.e. 10 coins. Value of 50 p
coins = 4 i.e. 8 coins. Value of 25 p coins = Rs. 3 i.e. 12 coins.
∴ Ratio of coins = 10 : 8 : 12 ⇒ 5 : 4 : 6.
∴ Number of rupee coins = 5/15 × 300 = 100.
Number of 50 P coins = 4/15 × 300 = 80
and Number of 25 P coins = 6/15 × 300 = 120
55. Some pens are divided among A, B, C and D. A gets twice the number of pens that B gets. C gets the same number of pens as D gets. If A gets 25 pens more than D and the ratio of the number of pens that B and C get is 2 : 3, then find the number of pens that D gets ?
· A. 100
· B. 50
· C. 75
· D. 25
· E. None of these.
Answer & Explanation
Answer: Option C
Explanation:
Let the number of pens that A, B, C and D get be a, b, c and d respectively.
a : b = 2 : 1
a = c + 25
b : c = 2 : 3
a : b : c : d = 4 : 2 : 3 : 3
a,d get 4p, 3p pens
=> 4p - 3p = 25 (given)
p = 25
=> D gets 3p = 3 * 25 = 75 pens.
56. Ram's age and Shyam's age are in the ratio 3 : 4. Seven years ago the ratio of their ages was 2: 3. Find the ratio of their ages five years hence?
· A. 33 : 26
· B. 14 : 15
· C. 15 : 14
· D. 26 : 33
· E. Cannot be determined
Answer & Explanation
Answer: Option D
Explanation:
Let ages of Ramu and Shyamu be x and y respectively.
x/y = 3/4 => x = 3/4 y
Also (x - 7) / (y - 7) = 2/3
=> 3x - 21 = 2y - 14
3x = 2y + 7
But x = 3/4 y
3 * 3/4 y = 2y + 7
9y = 8y + 28 => y = 28 years
Ratio of their ages five years hence
= (21 + 5) / (28 + 5) = 26/33.
57. Ratio of the ages of Mahesh and Nilesh is 5 : x. Mahesh is 18 years younger to Ramesh. After nine years Ramesh will be 47 years old. If the difference between the ages of Mahesh and Nilesh is same as the age of Ramesh, what is the value of x?
· A. 1
· B. 2
· C. 3
· D. 4
· E. None of these
Answer & Explanation
Answer: Option E
Explanation:
Let the present ages of Mahesh, Nilesh and Ramesh be m, n and r respectively.
m/n = 5/x ------ (1)
m = r - 18 ------ (2)
r + 9 = 47 ------ (3)
m - n = r ----- (4)
(3) => r = 47 - 9 = 38 years
(2) => m = 38 -18 = 20 years
(1) => 20/n = 5/x => n = 4x
(4) => 4x - 20 = 38
=> 4x = 58 => x = 14.5
58. Three numbers are in the ratio 5 : 6 : 7. The sum of its longest and smallest numbers equals the sum of the third number and 48. Find the third number?
· A. 36
· B. 42
· C. 48
· D. 54
· E. None of these
Answer & Explanation
Answer: Option C
Explanation:
Let the numbers be 5x, 6x, 7x.
Largest number = 7x.
Smallest number = 5x.
Third number = 6x.
7x + 5x = 6x + 48
6x = 48 => third number is 48.
59. Income and expenditure of a person are in the ratio 5 : 4. If the income of the person is Rs. 18000, then find his savings.
· A. Rs. 3600
· B. Rs. 3200
· C. Rs. 3000
· D. Rs. 3400
· E. None of these.
Answer & Explanation
Answer: Option A
Explanation:
Let the income and the expenditure of the person be Rs. 5x and Rs. 4x respectively.
Income, 5x = 18000 => x = 3600
Savings = Income - expenditure = 5x - 4x = x
So, savings = Rs. 3600.
60. Find the numbers which are in the ratio 3 : 2 : 4 such that the sum of the first and the second added to the difference of the third and the second is 21 ?
· A. 12, 8, 16
· B. 6, 4, 8
· C. 9, 6, 24
· D. 9, 6, 12
· E. None of these.
Answer & Explanation
Answer: Option D
Explanation:
Let the numbers be a, b and c.
Given that a, b and c are in the ratio 3 : 2 : 4.
let, a = 3x, b = 2x and c = 4x
Given, (a+b) + (c - b) = 21
= > a + b + c - b = 21 = > a + c = 21
= > 3x + 4x = 21
= >7x = 21 = > x = 3
a , b , c are 3x, 2x, 4x.
a, b, c are 9 , 6 , 12.
61. The ratio of the two natural numbers is 5 : 6. If a certain number is added to both the numbers, the ratio becomes 7 : 8. If the larger number exceeds the smaller number by 10, find the number added?
· A. 5
· B. 10
· C. 20
· D. 30
· E. None of these
Answer & Explanation
Answer: Option C
Explanation:
Let the two numbers be 5x and 6x.
Let the numbers added to both so that their ratio becomes 7 : 8 be k.
(5x + k) / (6x + k) = 7/8
=> 40x + 8k = 42x + 7k => k = 2x.
6x - 5x = 10 => x = 10
k = 2x = 20.
62. An amount of Rs.1560 was divided among A, B and C, in the ratio 1/2 : 1/3 : 1/4. Find the share of C?
· A. Rs. 300
· B. Rs. 320
· C. Rs. 280
· D. Rs. 360
· E. None of these
Answer & Explanation
Answer: Option D
Explanation:
Let the shares of A, B and C be a, b and c respectively.
a : b : c = 1/2 : 1/3 : 1/4
Let us express each term with a common denominator which is the last number divisible by the denominators of each term i.e., 12.
a : b : c = 6/12 : 4/12 : 3/12 = 6 : 4 : 3.
Share of C = 3/13 * 1560 = Rs. 360.
63. The ratio of the earnings of P and Q is 9 : 10. If the earnings of P increases by one-fourth and the earnings of Q decreases by one-fourth, then find the new ratio of their earnings?
· A. 2 : 3
· B. 3 : 2
· C. 4 : 3
· D. 3 : 4
· E. None of these
Answer & Explanation
Answer: Option B
Explanation:
Let the earnings of P and Q be Rs. 9x and Rs. 10x respectively.
New ration = [9x + 1/4(9x)]/[10x - 1/4(10x)]
=> [9x(1 + 1/4)]/[10x(1 - 1/4)] = 9/10 * (5/4)/(3/4) => 3/2.
64. Amar, Bhavan and Chetan divide an amount of Rs. 5600 among themselves in the ratio 3 : 6 : 5. If an amount of Rs. 400 is deducted from each of their shares, what will be the new ratio of their shares of the amount?
· A. 4 : 7 : 6
· B. 1 : 4 : 3
· C. 2 : 5 : 4
· D. 5 : 11 : 9
· E. None of these
Answer & Explanation
Answer: Option C
Explanation:
Let the shares of Amar, Bhavan and Chetan be Rs. 3x, Rs. 6x and Rs. 5x respectively.
3x + 6x + 5x = 5600 => 14x = 5600 => x = 400.
Required ratio = 3x - 400 : 6x - 400 : 5x - 400
= 3x - x : 6x - x : 5x - x
= 2x : 5x : 4x => 2 : 5 : 4
65. 64 boys and 40 girls form a group for social work. During their membership drive, same number of boys and girls joined the group. How many members does the group have now, if the ratio of boys to girls is 4 : 3?
· A. 150
· B. 172
· C. 136
· D. 164
· E. None of these
Answer & Explanation
Answer: Option E
Explanation:
Let us say x boys and x girls joined the group.
(64 + x) / (40 + x) = 4/3
192 + 3x = 160 + 4x => x = 32
Number of members in the group = 64 + x + 40 + x
= 104 + 2x = 168.
66. The ratio of the present ages of Giri and Hari is 5 : 8. 12 years hence, the ratio of their ages will be 11 : 14. Find the difference in their present ages?
· A. 10 years
· B. 6 years
· C. 3 years
· D. 5 years
· E. None of these
Answer & Explanation
Answer: Option B
Explanation:
Let the present ages of Giri and Hari be 5x and 8x years respectively.
(5x + 12) / (8x + 12) = 11/14
70x + 168 = 88x + 132 => x= 2
Difference in their ages will be the same at all times.
This difference = Difference of their present ages
= 8x - 5x = 3x = 6 years.
67. In a fort, there are 1200 soldiers. If each soldier consumes 3 kg per day, the provisions available in the fort will last for 30 days. If some more soldiers join, the provisions available will last for 25 days given each soldier consumes 2.5 kg per day. Find the number of soldiers joining the fort in that case?
· A. 420
· B. 528
· C. 494
· D. 464
· E. None of these
Answer & Explanation
Answer: Option B
Explanation:
Assume X soldiers join the fort. 1200 soldiers have provision for
1200(days for which provisions last them)(rate of consumption of each soldier)
= 1200(30)(3) kg
Also provisions available for (1200 + x) soldiers is (1200 + x)(25)(2.5) kg
As the same provisions are available
=> 1200(30)(3) = (1200 + x)(25)(2.5)
x = [1200(30)(3)]/[(25)(2.5)] - 1200
x = 528
68. 150 men consume 1050 kg of rice in 30 days. In how many days will 70 men consume 980 kg of rice?
· A. 30
· B. 60
· C. 45
· D. 90
· E. None of these
Answer & Explanation
Answer: Option B
Explanation:
Rate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day
Let us say 70 men take x days to consume 150 kg.
Quantity consumed by each item in x days = 7x/30 kg.
Quantity consumed by 70 men in x days = (7x/30)(70)kg
(7x/30)(70) = 980
x = (980 * 30)/490 => x = 60 days
69. If (x + y)/(2x + y) = 4/5, then find (2x + y)/(3x + y).
· A. 4/5
· B. 5/6
· C. 6/7
· D. 3/4
· E. None of these
Answer & Explanation
Answer: Option B
Explanation:
(x + y)/(2x + y) = 4/5
=> 5(x + y) = 4(2x + y) => 5x + 5y = 8x + 4y => y = 3x
Now, (2x + y)/(3x + y) = (2x + 3x)/(3x + 3x) = 5x/6x = 5/6.
70. There are two positive numbers in the ratio 5 : 8. If the larger number exceeds the smaller by 15, then find the smaller number?
· A. 25
· B. 30
· C. 20
· D. 35
· E. None of these
Answer & Explanation
Answer: Option A
Explanation:
Let the two positive numbers be 5x and 8x respectively.
8x - 5x = 15 => 3x = 15 => x = 5.
Smaller number = 5x = 25.
71. The weights of three boys are in the ratio 4:5:6. If the sum of the weights of the heaviest and the lightest boy is 45 kg more than the weight of the third boy, what is the weight of the lightest boy?
· A. 32 kg
· B. 36 kg
· C. 40 kg
· D. 44 kg
· E. None of these
Answer & Explanation
Answer: Option B
Explanation:
Let the weights of the three boys be 4k, 5k and 6k respectively.
4k + 6k = 5k + 45
=> 5k = 45 => k = 9
Therefore the weight of the lightest boy = 4k = 4 * 9 = 36 kg.
72. If p, q and r are positive integers and satisfy x = (p + q - r)/r = (p - q + r)/q = (q + r - p)/p, then the value of x is?
· A. 1/2
· B. 1
· C. -1/2
· D. -1
· E. None of these
Answer & Explanation
Answer: Option B
Explanation:
Hence, x = (p + q -
r)/r = (p - q + r)/q = (q + r - p)/p
=> x = (p + q - r + p - q + r + q + r - p)/(r + q + p)
=> x = (p + q + r)/(r + q + p) = 1.
73. What is the least number to be subtracted from 11, 15, 21 and 30 each so that the resultant numbers become proportional?
· A. 1
· B. 2
· C. 3
· D. 4
· E. None of these
Answer & Explanation
Answer: Option C
Explanation:
Let the least number to be subtracted be
'x', then 11 - x, 15 - x, 21 - x and 30 - x are in proportion.
<=> (11 - x):(15 - x) = (21 - x):(30 -x)(21 - x)
From the options, when x = 3
=> 8 * 27 = 12 * 18 => then x = 3. => (11 - x)(30 - x) = (15 - x)(21 -
x)
74. A gardener wants to plant trees in his garden in rows in such away that the number of trees in each row to be the same. If there are 24 rows the number of trees in each row is 42 if there are 12 more rows find the number of trees in each row?
· A. 63
· B. 28
· C. 48
· D. 32
· E. None of these
Answer & Explanation
Answer: Option B
Explanation:
Required
number of trees
= 24/36 * 42 = 28.
75. In an exam, a candidate secured 504 marks out of the maximum mark of M. If the maximum mark M is converted into 800 marks, he would have secured 384 marks. What is the value of M?
· A. 750
· B. 1200
· C. 1125
· D. 975
· E. None of these
Answer & Explanation
Answer: Option E
Explanation:
504/M =
384/800
M = (504 * 800)/384
M = 403200/384
M = 1050
76. Amar, Bhavan and Chetan divide an amount of Rs.5600 among themselves in the ratio 3:6:5. If an amount of Rs.400 is deducted from each of their shares, what will be the new ratio of their shares of the amount?
· A. 4:7:6
· B. 1:4:3
· C. 2:5:4
· D. 5:11:9
· E. None of these
Answer & Explanation
Answer: Option C
Explanation:
Let the shares of
Amar, Bhavan and Chetan be 3x, 6x and 5x respectively.
3x + 6x + 5x = 5600
14x = 5600 => x = 400
Required ratio = 3x - 400 : 6x - 400 : 5x - 400
= 3x - x : 6x - x : 5x - x
= 2x : 5x : 4x => 2:5:4
77. 64 boys and 40 girls form a group for social work. During their membership drive, the same number of boys and girls joined the group. How many members does the group have now, if the ratio of boys to girls is 4:3?
· A. 150
· B. 172
· C. 136
· D. 164
· E. None of these
Answer & Explanation
Answer: Option E
Explanation:
Let us say x boys and x girls joined the group.
(64 + x)/(40 + x) = 4/3
192 + 3x = 160 + 4x => x = 32
Number of members in the group = 64 + x + 40 + x
= 104 + 2x = 168.
78. The ratio of the present ages of Giri and Hari is 5:8. 12 years hence, the ratio of their ages will be 11:14. Find the difference in their present ages?
· A. 10 years
· B. 6 years
· C. 3 years
· D. 5 years
· E. None of these
Answer & Explanation
Answer: Option B
Explanation:
Let the present ages of Giri and Hari be 5x and 8x years respectively.
(5x + 12)/(8x + 12) = 11/14
70x + 168 = 88x + 132 => x = 2
Difference in their ages will be the same at all times.
This difference = Difference of their present ages
=> 8x - 5x = 3x => 6 years
79. Three number are in the ratio 5:6:7. The sum of its largest and smallest numbers equals the sum of the third number and 48. Find the third number?
· A. 36
· B. 42
· C. 48
· D. 54
· E. None of these
Answer & Explanation
Let the numbers be 5x, 6x and 7x.
Largest number = 7x
Smallest number = 5x
Third number = 6x
7x + 5x = 6x + 48
6x = 48
Third number is: 48.
80. Income and expenditure of a person are in the ratio 5:4. If the income of the person is Rs.18000, then find his savings?
· A. Rs.3600
· B. Rs.3200
· C. Rs.3000
· D. Rs.3400
· E. None of these
Answer & Explanation
Answer: Option A
Explanation:
Let the income and the expenditure of the person be Rs.5x and Rs.4x
respectively.
Income, 5x = 18000 => x = 3600
Savings = Income - expenditure = 5x - 4x = x
So, savings = Rs.3600.
81. If a:b = 4:1, then find (a - 3b)/(2a - b)?
· A. 2/7
· B. 1/7
· C. 3/7
· D. 5/7
· E. None of these
Answer & Explanation
Answer: Option B
Explanation:
a/b = 4/1 => a = 4b
(a - 3b)/(2a - b) = (4b - 3b)/(8b - b)
= b/7b => 1/7
82. if (x + y)/(2x + y) = 4/5, then find (2x + y)/(3x + y) ?
· A. 4/5
· B. 5/6
· C. 6/7
· D. 3/4
· E. None of these
Answer & Explanation
Answer: Option B
Explanation:
(x + y)/(2x + y) = 4/5
=> 5x + 5y = 8x + 4y => y = 3x
Now, (2x + y)/(3x + y) = 5x/6x = 5/6.
83. There are two positive numbers in the ratio 5:8. If the larger number exceeds the smaller by 15, then find the smaller number?
· A. 25
· B. 30
· C. 20
· D. 35
· E. None of these
Answer & Explanation
Answer: Option A
Explanation:
Let the two positive numbers be 5x and 8x respectively.
8x - 5x = 15
3x = 15 => x = 5
=> Smaller number = 5x = 25.
84. An amount of Rs.1560 was divided among A, B and C in the ratio 1/2:1/3:1/4. Find the share of C?
· A. Rs.300
· B. Rs.320
· C. Rs.280
· D. Rs.360
· E. None of these
Answer & Explanation
Answer: Option D
Explanation:
Let the shares of A, B and C be a, b and c respectively.
a:b:c = 1/2:1/3:1/4
a:b:c = 6/12:4/12:3:12 = 6:4:3
Share of C = 3/13 * 1560 = Rs.360.
85. The ratio of the earnings of P and Q is 9:10. If the earnings of P increases by one-fourth and the earnings of Q decreases by one-fourth, then find the new ratio of their earnings?
· A. 2:3
· B. 3:2
· C. 4:3
· D. 3:4
· E. None of these
Answer & Explanation
Answer: Option B
Explanation:
Let the earnings of P and Q be 9x and 10x respectively.
New ratio = [9x + 1/4 (9x)]/[10x - 1/4 (10x)]
=> 9*(1 + 1/4)/10*(1 - 1/4)
=> 9/10 * (5/4)/(3/4) = 3/2
86. x varies inversely as square of y. Given that y = 2 for x = 1. The value of x for y = 6 will be equal to:
· A. 3
· B. 9
· C. 1/3
· D. 1/9
Answer & Explanation
Answer: Option D
Explanation:
Given x = k/y2, where k is a constant.
Now, y = 2 and x = 1 gives k = 4.
x = 4/y2 => x = 4/62, when
y = 6 => x = 4/36 = 1/9.
87. If 10% of x = 20% of y, then x:y is equal to:
· A. 1:2
· B. 2:1
· C. 5:1
· D. 10:1
Answer & Explanation
Answer: Option B
Explanation:
10% of x = 20% of y
10x/100 = 20y/100 => x/10 = y/5
x/y = 10/5 = 2/1
x:y = 2:1.
88. Salaries of Ravi and Sumit are in the ratio 2:3. If the salary of each is increased by Rs. 4000, the new ratio becomes 40:57. What is Sumit's present salary?
· A. Rs. 17,000
· B. Rs. 20,000
· C. Rs. 25,500
· D. None of these
Answer & Explanation
Answer: Option D
Explanation:
Let the original salaries of Ravi and Sumit be Rs. 2x and Rs. 3x respectively.
Then, (2x + 4000)/(3x + 4000) = 40/57
6x = 68000 => 3x = 34000
Sumit's present salary = (3x + 4000) = 34000 + 4000 = Rs. 38,000.
89. If Rs. 510 be divided among A, B, C in such a way that A gets 2/3 of what B gets and B gets 1/4 of what C gets, then their shares are respectively:
· A. Rs. 120, Rs. 240, Rs. 150
· B. Rs. 60, Rs. 90, Rs. 360
· C. Rs. 150, Rs. 300, Rs. 60
· D. None of these
Answer & Explanation
Answer: Option B
Explanation:
(A = 2/3 B and B = 1/4 C) = A/B = 2/3 and B/C = 1/4
A:B = 2:3 and B:C = 1:4 = 3:12
A:B:C = 2:3:12
A;s share = 510 * 2/17 = Rs. 60
B's share = 510 * 3/17 = Rs. 90
C's share = 510 * 12/17 = Rs. 360.
90. A and B together have Rs. 1210. If 4/15 of A's amount is equal to 2/5 of B's amount, how much amount does B have?
· A. Rs. 460
· B. Rs. 484
· C. Rs. 550
· D. Rs. 664
Answer & Explanation
Answer: Option B
Explanation:
4/15 A = 2/5 B => A = (2/5 * 15/4)B
A =3/2 B => A/B = 3/2 => A:B = 3:2
B's share = 1210 * 2/5 = Rs. 484.
91. Seats for Mathematics, Physics and Biology in a school are in the ratio 5:7:8. There is a proposal to increase these seats by 40%, 50% and 75% respectively. What will be the ratio of increased seats?
· A. 2:3:4
· B. 6:7:8
· C. 6:8:9
· D. None of these
Answer & Explanation
Answer: Option A
Explanation:
Originally, let the number of seats for Mathematics, Physics and Biology be 5x, 7x and 8x respectively. Number of increased sears are (140% of 5x), (150% of 7x) and (175% of 8x)
i.e., (140/100 * 5x), (150/100 * 7x) and (175/100 * 8x)
i.e., 7x, 21x/2 and 14x
Required ratio = 7x:21x/2:14x
= 14x : 21x : 28x = 2:3:4
92. The salaries of A, B, C are in the ratio 2:3:5. If the increments of 15%, 10% and 20% are allowed respectively in their salaries, then what will be the new ratio of their salaries?
· A. 3:3:10
· B. 10:11:20
· C. 23:33:60
· D. Cannot be determined
Answer & Explanation
Answer: Option C
Explanation:
Let A = 2k, B = 3k and C = 5k
A's new salary = 115/100 of 2k = 23/10 k
B's new salary = 110/100 of 3k = 33/10 k
C's new salary = 120/100 of 5k = 6k
New ratio = 23k/10 : 33k/10 : 6k = 23:33:60
93. If Rs. 782 be divided into three parts, proportional to 1/2:2/3:3/4, then the first part is:
· A. Rs. 182
· B. Rs. 190
· C. Rs. 196
· D. Rs. 204
Answer & Explanation
Answer: Option D
Explanation:
Given ratio = 1/2:2/3:3/4 = 6:8:9
1st part = 782 * 6/23 = Rs. 204.
94. Two numbers are in the ratio 1:2. If 7 is added to both, their ratio changes to 3:5. The greatest number is:
· A. 24
· B. 26
· C. 28
· D. 32
Answer & Explanation
Answer: Option C
Explanation:
Let the numbers be x and 2x.
Then, (x + 7)/(2x + 7) = 3/5
x = 14
Greatest number = 2 * 14 = 28.
95. In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1:2:3. If there are Rs. 30 in all, how many 5 p coins are there?
· A. 50
· B. 100
· C. 150
· D. 200
Answer & Explanation
Answer: Option C
Explanation:
Let the number of 25 p, 10 p and 5 p coins be x, 2x and 3x respectively.
Then, sum of their values = [25x/100 + (10 * 2x)/100 + (5 * 3x)/100] = Rs. 60x/100
60x/100 = 30 => x = 50.
Hence, the number of 5 p coins = 3 * 50 = 150.
96. 1600 men have provisions for 28 days in the temple. If after 4 days, 400 men leave the temple, how long will the food last now?
· A. 28 days
· B. 30 days
· C. 32 days
· D. 35 days
Answer & Explanation
Answer: Option C
Explanation:
1600 ---- 28 days
1600 ---- 24
1200 ---- ?
1600*24 = 1200*x
x = 32 days
97. A fort of 2000 soldiers has provisions for 50 days. After 10 days some of them left and the food was now enough for the same period of 50 days as before. How many of them left?
· A. 400
· B. 600
· C. 800
· D. 1000
Answer & Explanation
Answer: Option A
Explanation:
2000 ---- 50
2000 ---- 40
x ----- 50
x*50 = 2000*40
x=1600
2000
-------
400
98. Divide Rs. 1500 among A, B and C so that A receives 1/3 as much as B and C together and B receives 2/3 as A and C together. A's share is?
· A. Rs.600
· B. Rs.525
· C. Rs.375
· D. Rs.0
Answer & Explanation
Answer: Option C
Explanation:
A+B+C = 1500
A = 1/3(B+C); B = 2/3(A+C)
A/(B+C) = 1/3
A = 1/4 * 1500 => 375
99. Rs.1170 is divided so that 4 times the first share, thrice the 2nd share and twice the third share amount to the same. What is the value of the third share?
· A. Rs.260
· B. Rs.270
· C. Rs.360
· D. Rs.540
Answer & Explanation
Answer: Option D
Explanation:
A+B+C = 1170
4A = 3B = 2C = x
A:B:C = 1/4:1/3:1/2 = 3:4:6
6/13 * 1170 = Rs.540
100. A, B and C play a cricket match. The ratio of the runs scored by them in the match is A:B = 2:3 and B:C = 2:5. If the total runs scored by all of them are 75, the runs scored by B are?
· A. 15
· B. 18
· C. 21
· D. 24
Answer & Explanation
Answer: Option B
Explanation:
A:B = 2:3
B:C = 2:5
A:B:C = 4:6:15
6/25 * 75 = 18
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