TIME SPEED DISTANCE EXAMPLE QUESTIONS PART 2
51)Three friends Rudra, Siva and Anvesh start to run around a circular stadium. They complete a revolution in 24, 36 and 30 seconds respectively. After how many minutes will they meet at the starting point ?
A) 60 B) 120
C) 360 D) 6
Answer & ExplanationAnswer: D) 6
Explanation:
For this we have to find the LCM of 24, 36 and 30
LCM of 24, 36 and 30 = 360 sec
360/60 min = 6 minutes.
52)If a student walks at the rate of 4 mts/min from his home, he is 4 minutes late for school, if he walks at the rate of 6 mts/min he reaches half an hour earlier. How far is his school from his home ?
A) 100 mts B) 96 mts
C) 98 mts D) 120 mts
Answer & ExplanationAnswer: C) 98 mts
Explanation:
Let the distance between home and school is 'x'.
Let actual time to reach be 't'.
Thus, x/4 = t + 4 ---- (1)
and x/6 = t - 30 -----(2)
Solving equation (1) and (2)
=> x = 98 mts.
53)A Bus is running at 9/10 of its own speed reached a place in 22 hours. How much time could be saved if the bus would run at its own speed ?
A) 1.5 hrs B) 1.7 hrs
C) 2.2 hrs D) 3.5 hrs
Answer & ExplanationAnswer: C) 2.2 hrs
Explanation:
Let the original Speed be "s" kmph
And the usual time be "t" hrs
Given that if the bus is running at 9s/10 kmph the time is 22 hrs
=> [9s/10] x 22 = t x s
=> 99/5 = t
=> t = 19.8 hrs
Hence, if bus runs at its own speed, the time saved = 22 - 19.8 = 2.2 hrs.
54)A train-A passes a stationary train B and a pole in 24 sec and 9 sec respectively. If the speed of train A is 48 kmph, what is the length of train B?
A) 200 mts B) 180 mts
C) 160 mts D) 145 mts
Answer & ExplanationAnswer: A) 200 mts
Explanation:
Length of train A = 48 x 9 x 5/18 = 120 mts
Length of train B = 48 x 24 x 5/18 - 120
=> 320 - 120 = 200 mts.
55)A jeep travels a certain distance taking 6 hrs in forward journey, during the return journey increased speed 12km/hr takes the times 4 hrs. What is the distance travelled by the jeep is ?
A) 244 km B) 144 km
C) 444 km D) 344 km
Answer & ExplanationAnswer: B) 144 km
Explanation:
Given a jeep travels a certain distance taking 6 hrs in forward journey
During the return journey, it takes 4 hrs with an increased speed 12 km/hr
Let 'x' be the distance.
Now, speed is given by distance/time.
Here the difference between both speeds = 12
x/4 − x/6 = 12
(3x − 2x) / 12 = 12
=> x = 144 km
Therefore, the distance travelled by the jeep in forward or return journey is x = 144km
56)K' cycled from A to B at 10 kmph and returned at the rate of 9 kmph. 'L' cycled both ways at 12 kmph. In the whole journey 'L' took 10 minutes less than 'K'. Find the distance between A and B ?
A) 32.1 km B) 15.23 km
C) 3.75 km D) 32.1 m
Answer & ExplanationAnswer: C) 3.75 km
Explanation:
Let 'd' be the distance between A and B
K -time = d/10 + d/9 = 19d/90 hours
L -time = 2d/12 = d/6 hours
We know that, 10 min = 1/6 hours
Thus, time difference between K and L is given as 10 minutes.
=> 19d/90 - d/6 = 1/6
=> (19d-15d)/90 = 1/6
=> 4d/90 = 1/6
Thus,
d= 15/4 km = 3.75 km.
hence the distance between A and B is 3.75 km
57)An express traveled at an average speed of 100 km/hr, stopping for 4 min after every 75 km. How long did it take to reach its destination 600 km from the starting point ?
A) 6 hrs 24 min B) 6 hrs
C) 7 hrs 21 min D) 6 hrs 28 min
Answer & ExplanationAnswer: D) 6 hrs 28 min
Explanation:
Time taken to cover 600 km = 600/100 = 6 hrs.
Number of stoppages = 600/75 - 1 = 7
Total time of stoppages = 4 x 7 = 28 min
Hence, total time taken = 6 hrs 28 min.
58)K is 50% faster than L. If L starts at 9 A.M. and K starts at 10 A.M. L travels at a speed of 50 km/hr. If L and K are 300 kms apart, The time when they meet when they travel in opposite direction is ?
A) 12 pm B) 1 pm
C) 11 am D) 11:30 am
Answer & ExplanationAnswer: A) 12 pm
Explanation:
let 't' be the time after which they met since L starts.
Given K is 50% faster than L
50t + 1.5*50(t-1) = 300
50t +75t = 300 + 75
t = 375 / 125 = 3 hrs past the time that L starts
So they meet at (9 + 3)hrs = 12:00 noon.
59)Laxmi and Prasanna set on a journey. Laxmi moves northwards at a speed of 20kmph and Prasanna moves southward at a speed of 30 kmph. How far will be Prasanna from Laxmi after 60 minutes ?
A) 24 km B) 50 km
C) 42 km D) 30 km
Answer & ExplanationAnswer: B) 50 km
Explanation:
We know 60 min = 1 hr
Total northward Laxmi's distance = 20kmph x 1hr = 20 km
Total southward Prasanna's distance = 30kmph x 1hr = 30 km
Total distance between Prasanna and Laxmi is = 20 + 30 = 50 km.
60)Joel travels the first 3 hours of his journey at 60 mph speed and the remaining 5 hours at 24 mph speed. What is the average speed of Joel's travel in kmph ?
A) 38 kmph B) 40 kmph
C) 60 kmph D) 54 kmph
Answer & ExplanationAnswer: C) 60 kmph
Explanation:
Average speed = Total distance / Total time.
Total distance traveled by Joel = Distance covered in the first 3 hours + Distance covered in the next 5 hours.
Distance covered in the first 3 hours = 3 x 60 = 180 miles
Distance covered in the next 5 hours = 5 x 24 = 120 miles
Therefore, total distance traveled = 180 + 120 = 300 miles.
Total time taken = 3 + 5 = 8 hours.
Average speed = 300/8 = 37.5 mph.
we know that 1 mile = 1.6 kms
=> 37.5 miles = 37.5 x 1.6 = 60 kms
Average speed in Kmph = 60 kmph.
61)Tilak rides on a cycle to a place at speed of 22 kmph and comes back at a speed of 20 kmph. If the time taken by him in the second case is 36 min. more than that of the first case, what is the total distance travelled by him (in km)?
A) 132 km B) 264 km
C) 134 km D) 236 km
Answer & ExplanationAnswer: B) 264 km
Explanation:
Let the distance travelled by Tilak in first case or second case = d kms
Now, from the given data,
d/20 = d/22 + 36 min
=> d/20 = d/22 + 3/5 hrs
=> d = 132 km.
Hence, the total distance travelled by him = d + d = 132 + 132 = 264 kms.
62)Chennai express left Hyderabad for Chennai at 14 : 30 hours, travelling at a speed of 60 kmph and Charminar Express left Hyderabad for Chennai on the same day at 16 : 30 hours, travelling at a speed of 80 kmph. How far away from Hyderabad will the two trains meet?
A) 360 kms B) 480 kms
C) 520 kms D) 240 kms
Answer & ExplanationAnswer: B) 480 kms
Explanation:
Now, the distance covered by Chennai express in 2 hrs = 60 x 2 = 120 kms
Let the Charminar Express takes 't' hrs to catch Chennai express
=> 80 x t = 60 x (2 + t)
=> 80 t = 120 + 60t
=> t = 6 hrs
Therefore, the distance away from Hyderabad the two trains meet = 80 x 6 = 480 kms.
63)A goods truck travels from a place at a certain time and at fixed speed. After 6hrs another truck leaves the same place and move in same direction of uniform speed of 90kmph. The truck catches up the goods truck in 4hrs. Find the speed of the goods truck ?
A) 36 kmph B) 32 kmph
C) 28 kmph D) 34 kmph
Answer & ExplanationAnswer: A) 36 kmph
Explanation:
Let the speed of goods truck be 'p' kmph
Distance covered by goods truck in 10hrs (4+6) = Distance covered by other truck in 4 hrs.
10p = 4 x 90
p = 36kmph.
Therefore, the speed of the goods truck is p = 36 kmph.
64)Akhil after travelling 50 km meets Raju who suggests him to go slower. He then proceeds at ¾ of his former speed and arrives at his destination 35 minutes late. Had the meeting occurred 24 km further Akhil would have reached its destination 25 minutes late. What is the initial speed of Akhil?
A) 48 kmph B) 36 kmph
C) 24 kmph D) 20 kmph
Answer & ExplanationAnswer: A) 48 kmph
Explanation:
Let the initial speed of Akhil be '4p' kmph
Then speed after decrease in speed = '3p' kmph
We know that,
Change in speed == Change in time
According to the given data,
24/3p − 24/4p = (35 − 25)/60=> p = 12
Hence, the initial speed of Akhil = 4p = 4 x 12 = 48 kmph.
65)Two trains are running with speeds 30 kmph and 58 kmph respectively in the same direction. A man in the slower train passes the faster train in 18 seconds. Find the length of the faster train?
A) 105 mts B) 115 mts
C) 120 mts D) 140 mts
Answer & ExplanationAnswer: D) 140 mts
Explanation:
Speeds of two trains = 30 kmph and 58 kmph
=> Relative speed = 58 - 30 = 28 kmph = 28 x 5/18 m/s = 70/9 m/s
Given a man takes time to cross length of faster train = 18 sec
Now, required Length of faster train = speed x time = 70/9 x 18 = 140 mts.
66)A Bus travels first half distance between two places with a speed of 40 kmph and the rest half distance with a speed of 60 kmph. The average speed of the Bus is ?
A) 48 kmph B) 50 kmph
C) 46 kmph D) 42 kmph
Answer & ExplanationAnswer: A) 48 kmph
Explanation:
we know that speed = distance traveled/time taken
let the total distance traveled by the car is 2x km.
then time taken by it to cover first half is x/60 hour.
and for second half is x/40 hour.
Then average speed= total distance travelled / total time taken.
i.e. 2x / [x/60+x/40]
=> 2x / (5x/120)
= 48 kmph.
67)Two trains running in opposite directions cross a pole placed on the platform in 47 seconds and 31 seconds respectively. If they cross each other in 33 seconds, what is the ratio of their speeds?
A) 1:7 B) 7:1
C) 2:3 D) 3:2
Answer & ExplanationAnswer: A) 1:7
Explanation:
Let the speed of the trains be x and y respectively
length of train1 = 47x
length of train2 = 31y
Relative speed= x + y
Time taken to cross each other = 33 s
=> (47x+31y) / x+y= 33
=> (47x + 31 y) = 33(x + y)
=> 14x = 2y
=> x/y = 2/14 = 1/7
= 1:7
68)Ali and Faizer are 27m apart. They both start walking and meet 9 hrs later, if they travel in the same direction and meet after 3 hrs if they walk in opposite dirction, Ali’s speed must most likely be ?
A) 9 m/h B) 3 m/h
C) 6 m/h D) 12 m/h
Answer & ExplanationAnswer: C) 6 m/h
Explanation:
let, speed of Ali=X mph and Faizer=Y mph
Now, relative speed when Ali is walking int the same direction with Faizer= (X-Y)mph
hence, according to question, 27/(X-Y)=9 ; solving X-Y=3; --- (1)
Now relative speed when walking in the opposite direction= (X+Y) mph
hence, according to question, 27/(X+y)=3; solving X+Y=9; --- (2)
solving 1 and 2 we get X=6 and Y=3, where X is the speed of Ali.
69)The ratio of the speeds of a car, a jeeps and a tractor is 3 : 5 : 2. The speed of the jeep is 250 per cent of the speed of the tractor and tractor covers 360 km in 12 hours. What is the average speed of car and jeep together?
A) 50 kmph B) 60 kmph
C) 70 kmph D) 80 kmph
Answer & ExplanationAnswer: B) 60 kmph
Explanation:
Speed of tractor = 360/12 = 30 kmph
Speed of jeep = 250 x 30/100 = 75 kmph
But, given ratio of speed of car, jeep and tractor is 3 : 5 : 2
Speed of car = 3 x 75/5 = 45 kmph
Required, average speed of car and jeep = 75 + 45/2 = 60 kmph.
70)A bike runs at the speed of 35 km/h when not serviced and runs at 55 km/h, when serviced. After servicing the bike covers a certain distance in 5 h. How much approximate time will the bike take to cover the same distance when not serviced?
A) 8 hrs B) 7.5 hrs
C) 7 hrs D) 6.5 hrs
Answer & ExplanationAnswer: A) 8 hrs
Explanation:
Given speed of the bike after servicing = 55 kmph
Time taken for travelling some distance at 55 kmph = 5 hrs
Then,
Distance = Speed x Time = 55 x 5 = 275 kms.
Now,
Speed of the bike before servicing = 35 kmph
Distance = 275 kms
Now, Time = Distance/Speed = 275/35 = 7.85 hrs =~ 8 hrs
71)Two cars, a Maruthi and a Toyato, start at the same time in opposite directions from two distinct points A and B. Starting from A, the Maruthi reaches B in 6 hrs 20 minutes and the Toyato starting from B, reaches A in 4 hrs 45 minutes. What is the speed of the Toyato, if the speed of the Maruthi is 60 Km/h?
A) 75 kmph B) 80 kmph
C) 86 kmph D) 90 kmph
Answer & ExplanationAnswer: B) 80 kmph
Explanation:
Let the distance between A and B = D
Given the speed of maruthi = 60 kmph
Maruthi reaches from A to B in 6 hrs 20 min = 6 + 20/60 = 6 1/3 hrs
Now, the distance between A & B = D = speed x time = 60 x 19/3 = 380 kms
As the distance is same for toyato also,
given time for toyato = 4 hrs 45 min = 4 + 45/60 = 4 3/4 = 19/4 hrs
speed of toyato = distance/time = 380/19/4 = 380 x 4/19 = 80 kmph.
72)An inspector is 228 meter behind the thief. The inspectorruns 42 meters and the thief runs 30 meters in a minute. Inwhat time will the inspector catch the thief?
A) 19 minutes B) 20 minutes
C) 18 minutes D) 21 minutes
Answer & ExplanationAnswer: A) 19 minutes
Explanation:
Inspector s 228 meter behind the thief and now aftersome x distance he will catch the thief. So
x/30 = 228+x/42 => x = 570 m
(228 + 570) / 42 = 19 min
73)Three cars A, B and C started from a point at 5 pm, 6 pm and 7 pm respectively and travelled at uniform speeds of 60 km/hr, 80 km/hr and x km/hr respectively in the same direction. If all the three met at another point at the same instant during their journey, then what is the value of x?
A) 120 B) 110
C) 105 D) 100
Answer & ExplanationAnswer: A) 120
Explanation:
Distance covered by A till 6pm = 60 km
Distance covered by A till 7 pm = 120 km
Time taken by B to catch A = 60/(80-60 ) = 3 hrs
So A and B will meet at 6pm + 3 hrs = 9pm
Since we know that all three met at the same time
The time taken by C to cover 120 km
difference will be = 9pm –7pm = 2hrs
Therefore,(x –60 )*2 = 120x = 120 km/hr
74)A plane is going in circles around an airport. The plane takes 3 minutes to complete one round. The angle of elevation of the plane from a point P on the ground at time t seconds is equal to that at time (t + 30) seconds. At time (t + x) seconds, the plane flies vertically above the point P. What is x equal to?
A) 75 seconds B) 90 seconds
C) 105 seconds D) 135 seconds
Answer & ExplanationAnswer: C) 105 seconds
Explanation:
Let the plane be at point A at t se
conds and at point B
after t + 30 seconds
Since the motion is uniform, we can say that at time t+15 seconds, the plane is above the point is
diametrically opposite to the point P from where the angle is same.
Now since the time taken to cover the full circ
le is 3 minutes (180
seconds), the time taken by the plane
to reach the diametrically opposite point will be 90 seconds.
So the time after which the plane reaches the point P will be = t+ 15 + 90 seconds = (t + 105 )seconds
75)Quantity I: Vipin can swim at 6 km/hr in still water. The river flows at 3 km/hr and it takes 8 hours more upstream then downstream for the same distance. How far is the place?
Quantity II: A man can row 25 km/hr in still water and the river is running at 15 km/hr. if the man takes 2 hr to row to a place and back, how far is the place?
A) Quantity I > Quantity II B) Quantity I ≥ Quantity II
C) Quantity I < Quantity II D) Quantity I < Quantity II
Answer & ExplanationAnswer: A) Quantity I > Quantity II
Explanation:
Quantity I: let d be the distance covered ATQ d/(6-3)-d/(6+3)=8 d=36km
Quantity II: ATQ d/(25-15)+d/(25+15)=2 D=16km
Hence Quantity I > Quantity II
76)A car runs at the speed of 50 kms per hour when not serviced and runs at 60 km./hr. when serviced. After servicing the car covers a certain distance in 6 hours. How much time will the car take to cover the same distance when not serviced?
A) 8.2 hrs B) 6.5 hrs
C) 8 hrs D) 7.2 hrs
Answer & ExplanationAnswer: D) 7.2 hrs
Explanation:
After servicing, the distance covered by car in 6 hours = 60 * 6 = 360 km Without servicing, speed of car = 50 kmph => Required time = Distance/speed = 360/50 = 7.2 hrs.
77)An aeroplane covers a certain distance at a speed of 240 kmph in 5 hours. To cover the same distance in 1 hours, it must travel at a speed of:
A. 300 kmph
B. 360 kmph
C. 600 kmph
D. 720 kmph
Answer: Option D
Explanation:
Distance = (240 x 5) = 1200 km.
Speed = Distance/Time
Speed = 1200/(5/3) km/hr. [We can write 1 2/3 hours as 5/3 hours]
Required speed = 1200 x (3/5)km/hr
= 720 km/hr.
78)If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
A.50 km
B.56 km
C.70 km
D.80 km
Answer: Option A
Explanation:
Let the actual distance travelled be x km.
Then, x/10 = (x + 20) / 14
14x = 10x + 200
4x = 200
x = 50 km.
79)Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
A.9
B.10
C.12
D.20
Answer: Option B
Explanation:
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = (9/54)x 60 = 10 min.
80)A car travelling with of its actual speed covers 42 km in 1 hr 40 min 48 sec. Find the actual speed of the car.
A.17 6/7km/hr
B.25 km/hr
C.30 km/hr
D.35 km/hr
Answer: Option D
Explanation:
Time taken = 1 hr 40 min 48 sec = 1 hr 40 4/5 min
= 1 51/75 hrs = 126/75 hrs
Let the actual speed be x km/hr.
Then, 5/7 x 126/75 = 42
42 x 7 x 75
x= ___________ = 35 km/hr.
5 x 126
81) In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is:
A.5 kmph
B.6 kmph
C.6.25 kmph
D.7.5 kmph
Answer: Option A
Explanation:
Let Abhay's speed be x km/hr.
Then, 30/x - 30/2x = 3
=> 6x = 30
x = 5 km/hr.
82)How many minutes Raman will take to cover a distance of 400 meters if he runs at a speed of 20 km/hr ?
a. 2 mins
b. 1.5 mins
c. 1⅕ mins
d. 2.5 mins
e. None of these
Answer & Explanation
Answer : [C]
Explanation :
⇒ Raman's speed = 20 km/hr = 20 × 5/18 = 50/9 m/sec
⇒ 400 × 9/50 = 1⅕ mins
83)John travelled from his town to city. John went to city by bicycle at the speed of 25 km/h and came back at the speed of 4 km/h. If John took 5 hours and 48 min to complete his journey, what is the distance between town and city ?
a. 15 km
b. 22 km
c. 20 km
d. 25 km
Answer & Explanation
Answer : [C]
Explanation :
⇒ Average speed of John = 2xy/x+y = 2 × 25 × 4 / 25 + 4= 200/29 km/h
⇒ Distance traveled = Speed × Time = 200/29 × 29/5 = 40 Km
⇒ Distance between city and town = 40/2 = 20 km
84)Speed of a train is 20 meters per second. It can cross a pole in 10 seconds. What is the length of train ?
a. 150 m
b. 250 m c. 200 m
d. 300 m
Answer & Explanation
Answer : [C]
Explanation :
⇒ Lenght of train = 20 × 10 = 200 meters
85)A car running at 65 km/h takes one hour to cover a distance. If the speed is reduced by 15 km/hour then in how much time it will cover the distance ?
a. 72 mins
b. 78 mins
c. 76 mins
d. None of these
Answer & Explanation
Answer : [B]
Explanation :
⇒Reduced speed = 65-15 = 50 km/h
⇒ Now car will take 65/50 × 60 mins = 78 mins
86)In a 100 m race A runs at a speed of 1.66 m/s. If A gives a start of 4m to B and still beats him by 12 seconds. What is the speed of B ?
a. 1 m/s
b. 1.33 m/s
c. 1.25 m/s
d. 1.5 m/s
Answer & Explanation
Answer : [B]
Explanation :
⇒Time taken by A to cover 100 meters = 60 seconds
⇒ Since A gives a start of 4 seconds then time takes by B = 72 seconds
⇒ B takes 72 seconds to cover 96 meters
⇒ Speed of B = 96/72 = 1.33 m/s
87)Without any stoppage a person travels a certain distance at an average speed of 42 km/hr and with stoppages he covers the same distance at an average speed of 28 km/hr. How many minutes per hour does he stop?
(a) 25 minutes
(b) 30 minutes
(c) 20 minutes
(d) None of these
Ans (C)
here, s1 = 42 and s2= 28
stoppage time/hr = (s1-s2) / s1
= (42 - 28) / 42
= 1/3 hour
= 20 minutes
88)Walking at the rate of 4 kmph a man cover certain distance in 2 hr 45 min. Running at a speed of 16.5 kmph the man will cover the same distance in.
A.12 min
B.25 min
C.40 min
D.60 min
Solution:
Option(C) is correct
Distance = Speed × time
Here time = 2hr 45 min = 11/4 hr
Distance = 4×11/4=11 km
New Speed =16.5 kmph
Therefore time = D/S=11/16.5=40 min
89) Two trains starting at the same time from 2 stations 200 km apart and going in opposite direction cross each other at a distance of 110 km from one of the stations. What is the ratio of their speeds?
A.11:9
B.7:3
C.18:4
D.None of these
Solution:
Option(A) is correct
In same time, they cover 110 km and 90 km respectively.
For the same time speed and distance is inversely proportional.
So ratio of their speed = 110:90 = 11: 9
90)A train covers a distance in 50 min, if it runs at a speed of 48 kmph on an average. The speed at which the train must run to reduce the time of journey to 40 min will be.
A.45 kmph
B.60 kmph
C.75 kmph
D.None of these
Solution:
Option(B) is correct
Time = 50/60=56 hr
Speed = 48 mph
Distance = S×T=48×5/6=40 km
Time = 40/60 hr
New speed = 40×3/2=60 kmph
91) A passenger train takes two hours less for a journey of 300 km if its speed is increased by 5 km/hr from its normal speed. The normal speed is:
A.35 km/hr
B.50 km/hr
C.25 km/hr
D.30 km/hr
Solution:
Option(C) is correct
Let the normal speed be 's' km/hr
Then new speed = (s+5) km/hr
300/s−2=300/s+5
On solving this equation we get:
s = 25 km/hr
92)In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is:
A.5 kmph
B.6 kmph
C.6.25 kmph
D.7.5 kmph
Answer: Option A
Explanation:
Let Abhay's speed be x km/hr.
Then, 30/x - 30/2x = 3
6x = 30
x = 5 km/hr.
93) The ratio between the speeds of two trains is 7 : 8. If the second train runs 400 km in 4 hours, then the speed of the first train is:
A.70 km/hr
B.75 km/hr
C.84 km/hr
D.87.5 km/hr
Answer: Option D
Explanation:
Let the speed of two trains be 7x and 8x km/hr.
Then, 8x = 400/4 = 100
x = 100/8= 12.5
94)A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is:
A.35.55 km/hr
B.36 km/hr
C.71.11 km/hr
D.71 km/hr
Answer: Option C
Explanation:
Total time taken =160/64 + 160/80hrs.=9/2 hrs.
Average speed = 320 x 2/9 km/hr = 71.11 km/hr.
95)A car started from Indore to Bhopal at a certain speed. The Car missed an accident at 40Kms away from Indore, then the driver decided to reduce Car speed to 4/5 of the original speed. Due to this, he reached Bhopal by a late of 1hr 15min.Suppose if he missed an accident at 80Km away from Indore and from then he maintained 4/5 of original speed then he would reach Bhopal by a late of 1hour. Then what is the original speed of the Car?
A. 20 km/hr
B. 40 km/hr
C. 60 km/hr
D. 80 km/hr
E. Cannot be determined
Answer & Explanation
Answer – B. 40 km/hr
Explanation :
(x+40/s) + 5/4 = 40/s + 5x/4s — — — 1
(x+40/s) + 1 = 80/s + 5(x-40)/4s — — — 2
s = 40
96)Two places A and B are at a certain distance. Ramu started from A towards B at a speed of 40 kmph. After 2 hours Raju started from B towards A at a speed of 60 kmph. If they meet at a place C then ratio of ratio of time taken by Raju to Ramu to reach Place C is 2:3. Then what is the distance between A and B?
A. 300 Km
B. 400 Km
C. 480 Km
D. 600 Km
E. Cannot be determined
Answer & Explanation
Answer – C. 480 Km
40t 1 +60t 2 = d
T 1 /t 2 = 3/2
T 1 – t 2 = 2
Solving d = 480 Km
97)Ramu started from A towards B at a speed of 20Km/hr and Raju started from B towards A. They crossed each other after one hour. Raju reached his destination 5/6 hour earlier than Ramu reached his destination.Then what is the distance between A and B?
A. 40 Km
B. 50 Km
C. 60 Km
D. 80 Km
E. Cannot be determined
Answer & Explanation
Answer – B. 50 Km
Explanation :
1 = x/20 = D-x/s 2
5/6 = D(1/20 – 1/s 2 )
D =50
98)Two Cars started at same time, same place and towards same direction. First Car goes at uniform speed of 12Km/hr. Second Car goes at speed of 4 Km/hr in first hour and increases it speed by 1 Km/hr for every hour. Then what is the distance traveled by car B when the both the Cars meet for the first time?
A. 196 Km
B. 198 Km
C. 200 Km
D. 204 Km
E. None
Answer & Explanation
Answer – D. 204 Km
Explanation :
12*x = x/2(2*4+(x-1)*1)
X= 17
D = 17*12 =204
99)A man traveled 100 km by Bike in 2 hours. He then traveled in Bus for 8 hrs and then Train in 9 hrs. Ratio of Speeds of Bus to Train is 4:5. If speed of train is 4/5 of Bike speed then the entire journey covered by him in Km is?
A. 516 Km
B. 616 Km
C. 716 Km
D. 816 Km
E. None
Answer & Explanation
Answer – C. 716 Km
Explanation :
Speed of train = 50
Bus = 32
Train = 40
Distance = 100+32*8+40*9 = 716
100)Car A leaves Delhi at a certain time, after 5 hours Car B leaves Delhi in the same direction as of A. Speed of Car A is 20Km/hr and Speed of Car B is 40Km/hr. In how much time Car B will be 20Km ahead of Car A?
A. 5 Hours
B. 6 Hours
C. 8 Hours
D. 11 Hours
E. None
Answer & Explanation
Answer – B. 6 Hours
Explanation :
20 =40*(t-5) – 20*t
T = 11
11-5 = 6
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